General Faculty Preferential Voting
For detailed information about the preferential voting system used in General Faculty elections, see the General Faculty Election Rules. This preferential system is a version of the HareCla rk system, which is a refinement of the Hare system used at UT Austin for many years. The Hare system has the inherent disadvantage that a random proce ss is involved in transferring any excess votes from candidates who have been elected; different choices can affect the results of the election. The HareClark system removes this defect by using fractional weighting for transferred excess votes. In addition, fractional weighting takes into account more of the information provided by the voters' indicated preferences. Counting votes electronically makes fractional weighting easy.
In the HareClark system, you need not rank all the candidates on the ballot, but skipping a number for those you do rank is not allowed. As a matter of strategy, there is one basic rule: if you prefer one candidate to another, then you should rank the one above the other, or at least rank the one who is perferred.
HareClark Example
This example illustrates the preferential voting system used in General Faculty elections. The process, a variation of the HareClark system, is described in Paragraph 3 of Policy Memorandum 1.301 (ByLaws of the Faculty Council), revised. The example uses the following assumptions:
That 100 voters cast final ballots to fill 5 positions from 10 nominees.
That those casting ballots are divided clearly into two groups, 60 conservatives and 40 liberals, whose members vote along strict party lines. The final ballot has 6 conservatives (A, B, C, D, E, F) and 4 liberals (W, X, Y, Z).
To make the details simple, assume:
 30 vote ACDEFB (That is, A first, C second, and so on.)
 30 vote BCDEFA
 10 vote WXYZ
 10 vote XYZW
 10 vote YZWX
 10 vote ZWXY
(The conservatives are evenly split with strong differing opinions on A and B, and are in agreement on the others. The liberals vote in such a way that the final result is bound to depend on random selection.)
Because of the 6040 split, we should expect that 3 conservatives and 2 liberals will be elected.
Quota
If n denotes the number of ballots cast and p denotes the number of positions to be filled, then the electoral quota is
q = (n/(p + 1)) + 1 = (100/(5 + 1)) + 1 = 16 2/3 + 1 rounded down, which gives q = 17.
Candidate

Vote


A

30 (Candidate A elected)

B

30 (Candidate B elected)

W

10

X

10

Y

10

Z

10

C

0

D

0

E

0

F

0

Candidate

Vote


C 
26 [(13/30)30 = 13 from
each of A and B.]
(Candidate C elected) 
W

10

X

10

Y

10

Z

10

D

0

E

0

F

0

Candidate

Vote


D 
9 [(9/26)(13/30)60 = 9]

W

10

X

10

Y

10

Z

10

E

0

F

0 
Choose one of E or F randomly to eliminate. Assume it is E. (Candidate E eliminated.) 
Candidate

Vote


D

9

W

10

X

10

Y

10

Z

10

F

0

(Candidate F eliminated.) 
Candidate

Vote


D

9

W

10

X

10

Y

10

Z

10

(Candidate D eliminated.) 
After fifth transfer (up from D)
Assume it is Z.
(Candidate Z eliminated.)
Candidate

Vote


W

20 [10 + 10 (from Z)]
(Candidate W elected) 
X

10

Y

10

Candidate

Vote


X

13 [10 + (3/20)20 (from W)]

Y

10

(Candidate Y eliminated.) 